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lower block size for keeping retired pages

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This commit is contained in:
daan 2019-08-20 09:45:50 -07:00
parent d81b800e12
commit ff88361329
1 changed files with 4 additions and 4 deletions
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8
src/page.c
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@ -71,7 +71,7 @@ static bool mi_page_is_valid_init(mi_page_t* page) {
mi_assert_internal(page->block_size > 0);
mi_assert_internal(page->used <= page->capacity);
mi_assert_internal(page->capacity <= page->reserved);
mi_segment_t* segment = _mi_page_segment(page);
uint8_t* start = _mi_page_start(segment,page,NULL);
mi_assert_internal(start == _mi_segment_page_start(segment,page,page->block_size,NULL));
@ -390,7 +390,7 @@ void _mi_page_retire(mi_page_t* page) {
// is the only page left with free blocks. It is not clear
// how to check this efficiently though... for now we just check
// if its neighbours are almost fully used.
if (mi_likely(page->block_size <= MI_MEDIUM_OBJ_SIZE_MAX)) {
if (mi_likely(page->block_size <= MI_SMALL_SIZE_MAX)) {
if (mi_page_mostly_used(page->prev) && mi_page_mostly_used(page->next)) {
_mi_stat_counter_increase(&_mi_stats_main.page_no_retire,1);
return; // dont't retire after all
@ -734,10 +734,10 @@ void* _mi_malloc_generic(mi_heap_t* heap, size_t size) mi_attr_noexcept
// call potential deferred free routines
_mi_deferred_free(heap, false);
// free delayed frees from other threads
_mi_heap_delayed_free(heap);
// huge allocation?
mi_page_t* page;
if (mi_unlikely(size > MI_LARGE_OBJ_SIZE_MAX)) {