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restrict max aligment boundary to prevent bug with segment determination (found by Matthew Parkinson).

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This commit is contained in:
daan 2021-12-17 11:40:46 -08:00
parent 60790e9013
commit 684c2c82a7
3 changed files with 6 additions and 1 deletions
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5
include/mimalloc-types.h
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@ -158,7 +158,10 @@ typedef int32_t mi_ssize_t;
#define MI_BIN_HUGE (73U)
#if (MI_LARGE_OBJ_WSIZE_MAX >= 655360)
#error "define more bins"
#error "mimalloc internal: define more bins"
#endif
#if (MI_ALIGNED_MAX > MI_SEGMENT_SIZE/2)
#error "mimalloc internal: the max aligned boundary is too large for the segment size"
#endif
// Used as a special value to encode block sizes in 32 bits.

1
include/mimalloc.h
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@ -166,6 +166,7 @@ mi_decl_export void mi_process_info(size_t* elapsed_msecs, size_t* user_msecs, s
// Note that `alignment` always follows `size` for consistency with unaligned
// allocation, but unfortunately this differs from `posix_memalign` and `aligned_alloc`.
// -------------------------------------------------------------------------------------
#define MI_ALIGNED_MAX (1024*1024UL) // maximum supported alignment is 1MiB
mi_decl_nodiscard mi_decl_export mi_decl_restrict void* mi_malloc_aligned(size_t size, size_t alignment) mi_attr_noexcept mi_attr_malloc mi_attr_alloc_size(1) mi_attr_alloc_align(2);
mi_decl_nodiscard mi_decl_export mi_decl_restrict void* mi_malloc_aligned_at(size_t size, size_t alignment, size_t offset) mi_attr_noexcept mi_attr_malloc mi_attr_alloc_size(1);